A conducting sphere of radius 5.0 cm carries a net charge of 7.5 µC.What is the surface charge density on the sphere? A)2.4 x 10^-2 C/m² B)1.4 x 10^-² C/m² C)9.5 x 10^-4 C/m² D)2.4 x 10^-4 C/m² E)6.0 x 10^-5 C/m²

Question

Quizplus · Accepted Answer

The surface charge density (σ) on a conducting sphere can be calculated using the formula:

σ = Q / A

where Q is the total charge on the sphere and A is the surface area of the sphere.

The total charge on the sphere is given as 7.5 µC.

The surface area of a sphere is given by the formula:

A = 4πr^2

where r is the radius of the sphere.

Substituting the values, we get:

A = 4π(0.05)^2 = 0.0314 m^2

Now, we can calculate the surface charge density:

σ = Q / A = (7.5 x 10^-6) / 0.0314

σ = 2.39 x 10^-4 C/m^2

Rounding off to two significant figures, we get:

σ = 2.4 x 10^-4 C/m^2

Therefore, the correct choice is D) 2.4 x 10^-4 C/m^2.

A Conducting Sphere of Radius 5