The candy company that makes M&M's claims that 10% of the M&M's it produces is green.Suppose that the candies are packaged at random in large bags of 200 M&M's.When we randomly pick a bag of M&M's,we may assume that this represents a simple random sample of size n = 200.Suppose we wish to test H₀: p = 0.10 versus H_a: p $\neq$ 0.10.Suppose that in the randomly selected bag of M&M's there are only 12 green M&M's.What is the value of the large-sample z statistic? A)z = -1.886 B)z = -0.444 C)z = 1.886 D)z = 0.444

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Quizplus · Accepted Answer

The large-sample z statistic is calculated using the formula $z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$, where $\hat{p}$ is the sample proportion, $p_0$ is the hypothesized population proportion, and $n$ is the sample size. Here, $\hat{p} = \frac{12}{200} = 0.06$, $p_0 = 0.10$, and $n = 200$. Plugging these values into the formula gives $z = \frac{0.06 - 0.10}{\sqrt{\frac{0.10(1-0.10)}{200}}} = -1.886$.

The Candy Company That Makes M&M's Claims That 10% of the M&M's