The candy company that makes M&M's claims that 10% of the M&M's it produces is green.Suppose that the candies are packaged at random in large bags of 200 M&M's.When we randomly pick a bag of M&M's,we may assume that this represents a simple random sample of size n = 200.Suppose we wish to test H₀: p = 0.10 versus H_a: p $\neq$0.10.Suppose that in the randomly selected bag of M&M's there are only 12 green M&M's.Calculate the value of the large-sample z statistic.What is the value of the corresponding P-value? A)P-value = 0.0297 B)P-value = 0.0593 C)P-value = 0.06 D)P-value = 0.3284

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Quizplus · Accepted Answer

The z statistic is calculated using the formula: z = (p̂ - p0) / sqrt(p0(1-p0)/n), where p̂ = 12/200 = 0.06, p0 = 0.10, and n = 200. The calculated z value is approximately -1.55. The corresponding P-value for a two-tailed test is approximately 0.0593.

The Candy Company That Makes M&M's Claims That 10% of the M&M's