What is the volume occupied by 11.0 g of propane gas,C₃H₈,at STP?

Question

Quizplus · Accepted Answer

Firstly, we need to use the ideal gas law equation, which is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. At STP (standard temperature and pressure), the temperature is 273 K and the pressure is 1 atm. We can find the number of moles by dividing the mass (11.0 g) by the molar mass of propane (44.1 g/mol):

n = 11.0 g / 44.1 g/mol = 0.249 mol

Plugging in the values for n, R, P, and T:

V = nRT/P = (0.249 mol)(0.08206 L*atm/mol*K)(273 K)/(1 atm) = 5.59 L

Therefore, the volume occupied by 11.0 g of propane gas at STP is 5.59 L, which is closest to choice C.

What Is the Volume Occupied by 11