If 1.00 x 1022 molecules of CO₂ gas is dissolved in 150.0 mL of aqueous solution,what is the molarity of the carbonic acid solution?

Question

Quizplus · Accepted Answer

The correct answer is A because the molarity of the carbonic acid solution is 0.111 M. This is because the number of moles of CO2 gas dissolved in the solution is 1.00 x 1022 molecules / 6.022 x 1023 molecules/mol = 1.66 x 10-2 mol. The volume of the solution is 150.0 mL = 0.1500 L. Therefore, the molarity of the solution is 1.66 x 10-2 mol / 0.1500 L = 0.111 M.

If 100 X 1022 Molecules of CO₂ Gas Is Dissolved in in 150.0