Given 25.0 mL of 0.200 M H₂SO₄,what is the mass of SO₃ dissolved in the sulfuric acid solution?

Question

Quizplus · Accepted Answer

To find the mass of SO₃ in the solution, first calculate the moles of H₂SO₄: 0.025 L * 0.200 mol/L = 0.005 mol H₂SO₄. Since each mole of H₂SO₄ contains one mole of SO₃, there are 0.005 mol of SO₃. The molar mass of SO₃ is 80.06 g/mol, so the mass is 0.005 mol * 80.06 g/mol = 0.401 g.

Given 250 ML of 0