What is the molarity of a acetic acid solution if 25.00 mL of HC₂H₃O₂ is required to neutralize 0.424 g of sodium carbonate (105.99 g/mol) ? 2 HC₂H₃O₂(aq) + Na₂CO₃(aq) → 2 NaC₂H₃O₂ (aq) + H₂O(l) + CO₂(g)
A) 0.0800 M
B) 0.100 M
C) 0.160 M
D) 0.200 M
E) 0.320 M
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