What is the molarity of a sodium hydroxide solution if 35.00 mL of NaOH is required to neutralize 1.555 g of KHP,that is KHC8H₄O₄ (204.23 g/mol)? KHC8H₄O₄(aq)+ NaOH(aq)→ KNaC8H₄O₄(aq)+ H₂O(l)

Question

Quizplus · Accepted Answer

First, we need to use the given mass of KHP to calculate the number of moles that were used in the titration:

moles of KHP = mass / molar mass = 1.555 g / 204.23 g/mol = 0.007616 mol KHP

Next, we need to use the balanced equation to determine the number of moles of NaOH that reacted with this amount of KHP:

1 mol KHP reacts with 1 mol NaOH

Therefore, moles of NaOH = 0.007616 mol NaOH

Finally, we can use this quantity and the volume of NaOH used to calculate the molarity of the NaOH solution:

Molarity (M) = moles of solute / volume of solution in liters

Volume of solution = 35.00 mL = 0.035 L

M = 0.007616 mol / 0.035 L = 0.2179... M

Rounding to three significant figures gives us a final answer of 0.218 M, which is choice B.

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