What is the molarity of a hydrochloric acid solution if 20.00 mL of HCl is required to neutralize 0.424 g of sodium carbonate (105.99 g/mol)? 2 HCl(aq)+ Na₂CO₃(aq)→ 2 NaCl(aq)+ H₂O(l)+ CO₂(g)

Question

Quizplus · Accepted Answer

1. Calculate the number of moles of sodium carbonate:
0.424 g ÷ 105.99 g/mol = 0.004 mol Na2CO3

2. From the balanced equation, 2 moles of HCl are required to react with 1 mole of Na2CO3:
0.004 mol Na2CO3 × 2 mol HCl/ 1 mol Na2CO3 = 0.008 mol HCl

3. Calculate the molarity of the hydrochloric acid solution:
Molarity = moles of solute ÷ volume of solution (in liters)
Molarity = 0.008 mol ÷ 0.020 L = 0.400 M

Therefore, the correct answer is D) 0.400 M.

What Is the Molarity of a Hydrochloric Acid Solution If