What is the molarity of a sulfuric acid solution if 30.00 mL of H₂SO₄ is required to neutralize 0.840 g of sodium hydrogen carbonate (84.01 g/mol)? H₂SO₄(aq)+ 2 NaHCO₃(aq)→ Na₂SO₄(aq)+ 2 H₂O(l)+ 2 CO₂(g)

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To find the molarity of the H₂SO₄ solution, first calculate the moles of NaHCO₃: 0.840 g / 84.01 g/mol = 0.01 mol. According to the balanced equation, 1 mol of H₂SO₄ reacts with 2 mol of NaHCO₃, so 0.01 mol NaHCO₃ requires 0.005 mol H₂SO₄. Molarity (M) = moles/volume (L), so M = 0.005 mol / 0.030 L = 0.167 M.

What Is the Molarity of a Sulfuric Acid Solution If