O₂ can be produced by the reaction 2 KClO₃(s) → 2 KCl(s) + 3 O₂(g). In one experiment 0.312 g of O₂ was formed. How much KClO₃ was decomposed?

Question

Quizplus · Accepted Answer

First, we need to use stoichiometry to find the amount of KClO₃ that was decomposed. From the balanced equation, we can see that 2 moles of KClO₃ react to produce 3 moles of O₂. Therefore, the amount of KClO₃ decomposed can be calculated as: (2/3) * (0.312 g O₂) / (122.55 g/mol O₂) * (286.20 g/mol KClO₃) = 0.797 g Therefore, the answer is B) 0.797 g.

O2 Can Be Produced by the Reaction 2 KClO3(s) →

O₂ Can Be Produced by the Reaction 2 KClO₃(s) →