When solutions of AgNO₃ and NaCl react, the balanced molecular equation is: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
How much AgCl is produced when 3.10 g of AgNO₃ and 0.600 g of NaCl react?

Question

Quizplus · Accepted Answer

The limiting reactant is AgNO3. Moles of AgNO3 = 3.10 g / 169.87 g/mol = 0.0182 mol. Moles of NaCl = 0.600 g / 58.44 g/mol = 0.0103 mol. AgNO3 is in excess. Moles of AgCl produced = 0.0103 mol. Mass of AgCl = 0.0103 mol * 143.32 g/mol = 1.47 g.

When Solutions of AgNO3 and NaCl React, the Balanced Molecular

When Solutions of AgNO₃ and NaCl React, the Balanced Molecular