How many calories of are required to heat 139 grams of water from 15°C to 88°C? (Assume that the specific heat of water is 1.00 cal/g·°C). A) 73 cal B) 2.1 × 10⁴ cal C) 1.0 × 10⁴ cal D) 1.2 × 10⁴ cal

Question

Quizplus · Accepted Answer

We can calculate the heat needed using the formula:
q = m*c*ΔT
where q is the heat needed, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.

Plugging in the values, we get:
q = 139 g * 1.00 cal/g·°C * (88°C - 15°C) = 1.0 × 10^14 cal

Therefore, the answer is C) 1.0 × 10^14 cal.

How Many Calories of Are Required to Heat 139 Grams