If a certain amount of heat is added to a 30.0 gram sample of water the temperature of the sample increases from 27.0°C to 57.0°C. If this same amount of heat is added to a 90.0 gram sample of water initially at 40.0°C what will be the final temperature of the water?
A) 30.0°C
B) 50.0°C
C) 70.0°C
D) 90.0°C

Question

Quizplus · Accepted Answer

We can use the formula Q = mCΔT, where Q is the amount of heat added, m is the mass, C is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature.
For the first sample of water:
Q = (30.0 g)(4.184 J/g°C)(57.0°C - 27.0°C) = 3,604.8 J
For the second sample of water:
3,604.8 J = (90.0 g)(4.184 J/g°C)(Tf - 40.0°C)
Tf - 40.0°C = 10.955
Tf = 50.955°C, which rounds to 50.0°C.

If a Certain Amount of Heat Is Added to a 30.0