Small populations of a diminutive rodent, each with 100 individuals, live on two small neighboring islands, Rack and Oon. The Rack population is fixed for the A allele at the Agility gene; the Oon population is fixed for the a allele at the Agility gene. Ten individuals from Rack get carried on a drifting fallen tree trunk to Oon. Assuming the drifting individuals arrived at the start of the breeding season and that the rodents breed every year and die once they've raised their offspring, what are the genotype frequencies in the Oon population the year after the accidental migration event? A)AA 0.0; Aa 0.0; aa 1.0 B)AA (1/11)²; Aa 2(1/11)(10/11); aa (10/11)² C)AA (10/11)²; Aa 2(1/11)(10/11); aa (1/11)² D)AA 1.0; Aa 0.0; aa 1.0 E)The genotype frequencies cannot be determined from the information provided.

Question

Quizplus · Accepted Answer

Given the initial conditions, the Oon population has 100 individuals with the aa genotype, and 10 individuals from Rack with the AA genotype are added. This results in a total population of 110, with 10 AA and 100 aa individuals. Since A and a alleles are equally likely to be passed on, the first generation after migration will have AA, Aa, and aa genotypes. The AA genotype frequency is calculated as the square of the frequency of the A allele (which is incorrect here because there are no AA offspring from aa parents), the Aa genotype frequency is 2*(frequency of A allele)*(frequency of a allele) due to heterozygote formation, and the aa genotype frequency is the square of the frequency of the a allele (also incorrect in this context because it doesn't account for the new A alleles). The correct calculation involves considering the new allele frequencies and how they combine in offspring.

Small Populations of a Diminutive Rodent, Each with 100 Individuals