You are given the following information about a population: • There are two alleles: C and c.
• C codes for green hair and c codes for white hair.
• C is dominant over c.
• The frequency of the c allele is 0.3.
• The population is comprised of 100 individuals.
Assuming the population is in Hardy-Weinberg equilibrium, how many individuals have green hair?
A)49% of the population will have green hair.
B)81% of the population will have green hair.
C)9% of the population will have green hair.
D)51% of the population will have green hair.

Question

Quizplus · Accepted Answer

Given that the frequency of the c allele is 0.3, the frequency of the C allele is 1 - 0.3 = 0.7. In a Hardy-Weinberg equilibrium, the frequency of the genotypes can be calculated using the equation p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele (C) and q is the frequency of the recessive allele (c). The frequency of individuals with green hair (CC or Cc) is p^2 + 2pq = 0.7^2 + 2(0.7)(0.3) = 0.49 + 0.42 = 0.91 or 91%. Since the population is 100 individuals, 91% of 100 is 91 individuals, which is closest to the option stating 81% of the population will have green hair, considering the options provided.

You Are Given the Following Information About a Population: •