The fruit fly cross shown here analyzes the transmission of two genes in the X chromosome. The male parent has mutant alleles for both the white gene (w^-) and the crossveinless gene (cv^-). The female parent has nonmutant forms of these genes (w⁺ and cw⁺). A cross between siblings of the F₁generation-a red-eyed, crossveined female and a red-eyed, crossveined male-generates F₂ progeny. Examine the genotype of the F₂ male progeny. Notice that the progeny fall into two groups. Refer to the figure below when answering the following question. Why are the female progeny from the F₁ cross shown in the figure not used for linkage analysis?

A)All F₂ females exhibit the genotype associated with genes located in the X donated by the male parent from the F₁ cross.
B)F₂ females reveal the genotype of the F₁ female parent as well as the genotype of recombinants.
C)All F₂ females have a wild-type phenotype of red eyes and cross-veined wings.
D)F₂females appear to assort independently because they exhibit a 1:1:1:1 ratio.
E)F₂male progeny far outnumber the F₂female progeny.

Genes That Are Linked Do Not Show