In the F₂ generation of a homozygous round (AA) × homozygous wrinkled (aa) cross in peas, two round seeds are chosen at random. What is the probability that one is AA and the other Aa? A)(1/3)² B)(2/3)(1/3) C)2(2/3)(1/3) D)(2/3)²

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In the F1 generation of a homozygous round (AA) × homozygous wrinkled (aa) cross, all offspring are Aa (heterozygous round). When these F1 individuals self-pollinate to produce the F2 generation, the genotype ratio is 1AA:2Aa:1aa, which translates to a phenotype ratio of 3 round: 1 wrinkled. For two round seeds, the probability of picking one AA and one Aa is 2*(1/3)*(2/3), because there are two ways this can happen (AA then Aa or Aa then AA), with a 1/3 chance for AA and a 2/3 chance for Aa among the round seeds.

In the F2 Generation of a Homozygous Round (AA) ×

In the F₂ Generation of a Homozygous Round (AA) ×