In the F₂ generation of a homozygous round (AA) × homozygous wrinkled (aa) cross in peas, three seeds are chosen at random. What is the probability that all three seeds are round? A)(1/4)³ B)3(1/4)(3/4)² C)3(1/4)²(3/4) D)(3/4)³

Question

Quizplus · Accepted Answer

In a cross between a homozygous round (AA) and a homozygous wrinkled (aa) pea plant, all offspring (F1 generation) will be heterozygous (Aa) and exhibit the dominant round phenotype. Therefore, the probability of picking a round seed is 1 (or 100%). For three seeds chosen at random, the probability that all three are round is 1^3 = 1, which is equivalent to (3/4)^3 when considering the dominant phenotype's complete dominance and expression in the offspring.

In the F2 Generation of a Homozygous Round (AA) ×

In the F₂ Generation of a Homozygous Round (AA) ×