The mass of oxygen present in 11.7 g of AL₂(CO₃)₃ is ________.

Question

Quizplus · Accepted Answer

The molecular formula for AL₂(CO₃)₃ is aluminum carbonate, where the molar mass is calculated as follows: Al = 26.98 g/mol, C = 12.01 g/mol, O = 16.00 g/mol. The molar mass of AL₂(CO₃)₃ = 2(26.98) + 3[12.01 + 3(16.00)] = 233.99 g/mol. The mass of oxygen in one mole of AL₂(CO₃)₃ = 3 * 3 * 16.00 = 144.00 g. The mass of oxygen in 11.7 g of AL₂(CO₃)₃ = (144.00/233.99) * 11.7 ≈ 7.20 g.

The Mass of Oxygen Present in 11