What is the mass of sulfur that will react with 0.527 g of copper metal to yield copper (I) sulfide?

Question

Quizplus · Accepted Answer

Copper (I) sulfide has the formula Cu2S. The molar mass of copper (Cu) is approximately 63.55 g/mol, and sulfur (S) is approximately 32.07 g/mol. First, calculate the moles of copper: 0.527 g / 63.55 g/mol = 0.00829 mol. Since the formula is Cu2S, 2 moles of copper react with 1 mole of sulfur. Therefore, moles of sulfur needed = 0.00829 mol / 2 = 0.004145 mol. The mass of sulfur = 0.004145 mol * 32.07 g/mol = 0.132 g.

What Is the Mass of Sulfur That Will React with 0.527