0.842 g chlorine will combine with ________ g of sulfur to produce SCL₂.

Question

Quizplus · Accepted Answer

The molecular weight of chlorine (Cl) is approximately 35.5 g/mol, and for sulfur (S), it is approximately 32.1 g/mol. The chemical formula SCl₂ indicates that one mole of sulfur combines with two moles of chlorine. Therefore, the mass of sulfur that will combine with chlorine can be calculated using the stoichiometry of the reaction. For chlorine weighing 0.842 g (which is 0.842 / 71 = 0.01186 moles, since the molar mass of Cl₂ is approximately 71 g/mol), the moles of sulfur needed would be the same (0.01186 moles, since the ratio is 1:1 from S to Cl₂ in terms of moles). Thus, the mass of sulfur required is 0.01186 moles * 32.1 g/mol = 0.380586 g, which rounds to approximately 0.379 g.

0842 G Chlorine Will Combine with ________ G of Sulfur