Determine the percent yield of an experiment in which 1.00 mole of NaHCO₃ was consumed and 22.0 g of carbon dioxide was isolated. NaHCO₃ → Na₂CO₃ + CO₂ + H₂O

Question

Quizplus · Accepted Answer

1.00 mole of NaHCO3 produces 1.00 mole of CO2. The molar mass of CO2 is 44.0 g/mol. Therefore, the theoretical yield of CO2 is 44.0 g. The percent yield is calculated as (actual yield / theoretical yield) x 100%. In this case, the actual yield is 22.0 g and the theoretical yield is 44.0 g. Therefore, the percent yield is (22.0 g / 44.0 g) x 100% = 50.0%.

Determine the Percent Yield of an Experiment in Which 1