If the empirical formula is C₄H₃N and the molecular weight is 130 g/mole, then the molecular formula is ________.

Question

Quizplus · Accepted Answer

1. Calculate the empirical formula mass: C₄H₃N = (4x12.01)+(3x1.01)+(1x14.01) = 79.06 g/mol
2. Divide the molecular weight by the empirical formula mass: 130 g/mol ÷ 79.06 g/mol = 1.645...
3. Round this number to the nearest integer to get the ratio of the molecular formula to the empirical formula: 2
4. Multiply the subscripts in the empirical formula by 2 to get the molecular formula: C4 x 2 = C8; H3 x 2 = H6; N x 2 = N₂
5. Molecular formula: C₈H₆N₂

If the Empirical Formula Is C₄H₃N and the Molecular Weight