The voltaic cell composed of Co(s),Co²⁺(aq),Cu(s),and Cu²⁺(aq)has E°_cell = 0.62 V.If E° of the cathode half-cell is 0.34 V,what is E° of the anode half-cell? Cu²⁺(aq)+ Co(s)→ Cu(s)+ Co²⁺(aq)

Question

Quizplus · Accepted Answer

We can use the formula: E°cell = E°cathode - E°anode
Given that E°cell = 0.62 V and E°cathode = 0.34 V, we can solve for E°anode:
0.62 V = 0.34 V - E°anode
E°anode = 0.34 V - 0.62 V = -0.28 V
Therefore, the answer is A.

The Voltaic Cell Composed of Co(s),Co2+(aq),Cu(s),and Cu2+(aq)has E°cell = 0

The Voltaic Cell Composed of Co(s),Co²⁺(aq),Cu(s),and Cu²⁺(aq)has E°_cell = 0