Based on the data presented below,which is the strongest oxidizing agent? [PtCl₄]^2-(aq) + 2e^-
Pt(s) + 4Cl^-(aq) E° = 0.755V
RuO₄(s) + 8H⁺(aq) + 8e^- Ru(s) + 4H₂O(l) E° = 1.038V
FeO₄^2-(aq) + 8H⁺(aq) + 3e^- Fe³⁺(aq) +4H₂O(l) E° = 2.07 V
H₄XeO₆(aq) + 2H⁺(aq) + 2e^- XeO₃(aq) +3H₂O(l) E° = 2.42 V

Question

Based on the data presented below,which is the strongest oxidizing agent? [PtCl₄]^2-(aq) + 2e^-

Based on the data presented below,which is the strongest oxidizing agent? [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> <sup> </sup> Pt(s) + 4Cl<sup>-</sup>(aq) E° = 0.755V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> Ru(s) + 4H<sub>2</sub>O(l) E° = 1.038V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> Fe<sup>3+</sup>(aq) +4H<sub>2</sub>O(l) E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> XeO<sub>3</sub>(aq) +3H<sub>2</sub>O(l) E° = 2.42 V A) [PtCl<sub>4</sub>]<sup>2-</sup>(aq) B) RuO<sub>4</sub>(s) C) HFeO<sub>4</sub><sup>-</sup>(aq) D) H<sub>4</sub>XeO<sub>6</sub>(aq) E) Cl<sup>-</sup>(aq)

Pt(s) + 4Cl^-(aq) E° = 0.755V
RuO₄(s) + 8H⁺(aq) + 8e^-

Ru(s) + 4H₂O(l) E° = 1.038V
FeO₄^2-(aq) + 8H⁺(aq) + 3e^-

Fe³⁺(aq) +4H₂O(l) E° = 2.07 V
H₄XeO₆(aq) + 2H⁺(aq) + 2e^-

XeO₃(aq) +3H₂O(l) E° = 2.42 V

Quizplus · Accepted Answer

The stronger the oxidizing agent, the higher the E° value. Among the given options, H₄XeO₆(aq) has the highest E° value of 2.42V, indicating it is the strongest oxidizing agent. This is followed by FeO₄^2-(aq) with an E° value of 2.07V, RuO₄(s) with an E° value of 1.038V, [PtCl₄]^2-(aq) with an E° value of 0.755V, and Cl^-(aq) with an E° value of 0V. Therefore, H₄XeO₆(aq) is the best choice as the strongest oxidizing agent.

Based on the Data Presented Below,which Is the Strongest Oxidizing