At elevated temperatures,hydrogen iodide may decompose to form hydrogen gas and iodine gas,as follows. 2HI(g) H₂(g) + I₂(g)
In a particular experiment,the concentrations at equilibrium were measured to be [HI] = 0.85
Mol/L,[I₂] = 0.60 mol/L,and [H₂] = 0.27 mol/L.What is K_c for the above reaction?

Question

At elevated temperatures,hydrogen iodide may decompose to form hydrogen gas and iodine gas,as follows. 2HI(g)

H₂(g) + I₂(g)
In a particular experiment,the concentrations at equilibrium were measured to be [HI] = 0.85
Mol/L,[I₂] = 0.60 mol/L,and [H₂] = 0.27 mol/L.What is K_c for the above reaction?

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The Answer of At elevated temperatures,hydrogen iodide may decompose to form hydrogen gas and iodine gas,as follows. 2HI(g) H₂(g)+ I₂(g) In a particular experiment,the concentrations at equilibrium were measured to be [HI] = 0.85 Mol/L,[I₂] = 0.60 mol/L,and [H₂] = 0.27 mol/L.What is K_c for the above reaction?

At Elevated Temperatures,hydrogen Iodide May Decompose to Form Hydrogen Gas