Let $ { \vec { F } } = - 2 x z \vec { i } + 5 ( y - x ) \vec { j } + 5 x \vec { k }$ (a)Use Stokes' Theorem to find the circulation of $\vec { F}$ around the circle of radius a, $\vec { r } ( t ) = a \cos t \vec { i } + \alpha \sin t \vec { j }$ for 0 $\le$ t $\le$ 2 $\pi$.
(b)Use this result to find the $\vec { k }$ component of $\operatorname { curl } \vec { F } ( 0,0,0 )$

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The Answer of Let $ { \vec { F } } = - 2 x z \vec { i } + 5 ( y - x ) \vec { j } + 5 x \vec { k }$ (a)Use Stokes' Theorem to find the circulation of $\vec { F}$ around the circle of radius a, $\vec { r } ( t ) = a \cos t \vec { i } + \alpha \sin t \vec { j }$ for 0 $\le$ t $\le$ 2 $\pi$.
(b)Use this result to find the $\vec { k }$ component of $\operatorname { curl } \vec { F } ( 0,0,0 )$

Let F⃗=−2xzi⃗+5(y−x)j⃗+5xk⃗ { \vec { F } } = - 2 x z \vec { i } + 5 ( y - x ) \vec { j } + 5 x \vec { k }F=−2xzi+5(y−x)j​+5xk

Let ${ \vec { F } } = - 2 x z \vec { i } + 5 ( y - x ) \vec { j } + 5 x \vec { k }$