Question 1

Solve the problem.
-The odds in favor of Jerome beating his friend in a round of golf are 1 : 7. Find the probability that Jerome will beat his friend. 
A) $ \frac{1}{9} $
B) $ \frac{1}{8} $
C) $ \frac{1}{4} $
D) 1

Accepted Answer

The answer of Solve the problem.
-The odds in favor of...

Question 2

Solve the problem.
-In a certain town, 25% of people commute to work by bicycle. If a person is selected randomly From the town, what are the odds against selecting someone who commutes by bicycle?
A) 1 to 3
B)3 to 4
C)4to 1
D)3 to 1

Accepted Answer

The probability of selecting someone who commutes by bicycle is 25%, or 1/4. The probability of not selecting someone who commutes by bicycle is 75%, or 3/4. The odds against selecting someone who commutes by bicycle are the ratio of not commuting by bicycle to commuting by bicycle, which is 3:1.

Question 3

Solve the problem.
-The odds against Muffy beating her friend in a round of golf are 1 : 6. Find the probability that Muffy will lose.
A) 18
B) 17
C) 27
D) 67

Accepted Answer

The answer of Solve the problem.
-The odds against Muffy beating...

Question 4

Solve the problem.
-The odds in favor of a horse winning a race are posted as 8 : 7. Find the probability that the horse Will lose the race. 
A) $ \frac{7}{8} $
B) $ \frac{8}{15} $
C) $ \frac{7}{15} $
D) $ \frac{7}{17} $

Accepted Answer

The odds in favor of winning are 8:7, meaning for every 8 chances of winning, there are 7 chances of losing. The total outcomes are 8 + 7 = 15. The probability of losing is the number of losing outcomes over the total outcomes, which is $ \frac{7}{15} $.

Question 5

Solve the problem.
-The odds in favor of a horse winning a race are posted as 4 : 3. Find the probability that the horse Will win the race. 
A) $ \frac{3}{4} $
B) $ \frac{3}{7} $
C) $ \frac{4}{7} $
D) $ \frac{1}{2} $

Accepted Answer

The odds in favor of an event are given as the ratio of the probability of the event happening to the probability of it not happening. Here, the odds are 4:3, meaning for every 4 times the horse wins, it loses 3 times. To find the probability of winning, we calculate the ratio of wins to total outcomes (wins + losses), which is $ \frac{4}{4+3} = \frac{4}{7} $.

Question 6

Solve the problem.
-The odds in favor of Carl beating his friend in a round of golf are 9 : 2. Find the probability that Carl will beat his friend. 
A) $ \frac{2}{9} $
B) $ \frac{2}{11} $
C) $ \frac{9}{11} $
D) $ \frac{3}{4} $

Accepted Answer

The probability is calculated by dividing the number of favorable outcomes by the total number of outcomes. Here, the odds in favor of Carl are 9:2, meaning there are 9 favorable outcomes for Carl and 2 unfavorable. The total outcomes are 9 + 2 = 11. Thus, the probability of Carl winning is $ \frac{9}{11} $.

Question 7

Solve the problem.
-In a certain town, 5% of people commute to work by bicycle. If a person is selected randomly from The town, what are the odds in favor of selecting someone who commutes by bicycle?
A) 19 to 1
B)20 to 19
C) 1 to 19
D) 1 to 20

Accepted Answer

The odds in favor of selecting someone who commutes by bicycle are 5 to 95, or simplified, 1 to 19. This is because 5% commute by bicycle, meaning 95% do not, so the odds are 5:95 or simplified to 1:19.

Question 8

Solve the problem.
-If it has been determined that the probability of an earthquake occurring on a certain day in a Certain area is 0.01, what are the odds against an earthquake?
A) 100 to 1
B)98 to 1
C)99to 1
D)1 to 100

Accepted Answer

The odds against an event are calculated as the ratio of the probability of the event not happening to the probability of the event happening. Here, the probability of not having an earthquake is 0.99 (1 - 0.01), and the probability of having an earthquake is 0.01. Therefore, the odds against an earthquake are 0.99 to 0.01, which simplifies to 99 to 1.

Question 9

Find the probability.
-Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed Well. Two are drawn. What are the odds in favor of the sum of the numbers on the two selected Slips is not 6?
A) 9 to 1
B)21 to 2
C)19 to 2
D)19 to 1

Accepted Answer

To find the odds in favor of the sum not being 6, first determine the total number of ways to draw 2 slips from 7, which is $C(7,2) = \frac{7!}{2!(7-2)!} = 21$. Then, find the combinations that sum to 6: (1,5), (2,4), and (5,1), (4,2) - but since drawing order doesn't matter, we only count each unique pair once, leaving us with 2 unique pairs. Thus, there are 21 - 2 = 19 outcomes where the sum is not 6. The odds in favor are 19 successful outcomes to 2 unsuccessful ones, or 19 to 2.

Question 10

Solve the problem.
-If it has been determined that the probability of an earthquake occurring on a certain day in a Certain area is 0.01, what are the odds in favor of an earthquake?
A) 1 to 98
B) 1 to 99
C) 1 to 100
D) 99 to 1

Accepted Answer

The odds in favor of an earthquake are calculated by taking the probability of the event happening (1 in 100 or 0.01) and comparing it to the probability of it not happening (99 in 100 or 0.99), which simplifies to 1 to 99.

Question 11

Solve the problem.
-If the probability that an identified hurricane will make a direct hit on a certain stretch of beach is 0.04, what are the odds in favor of a direct hit?
A) 1 to 23
B) 24 to 1
C)1 to 25
D) 1 to 24

Accepted Answer

The probability of a direct hit is 0.04, which means the probability of not hitting is 0.96. The odds in favor are calculated as the ratio of the probability of the event happening to it not happening: 0.04 / 0.96 = 1 / 24.

Question 12

Solve the problem.
-The odds against Chip beating his friend in a round of golf are 1 : 6. Find the probability that Chip Will beat his friend. 
A) $ \frac{6}{7} $
B) $ \frac{1}{8} $
C) $ \frac{3}{4} $
D) $ \frac{1}{7} $

Accepted Answer

The odds against Chip beating his friend are 1 : 6, which means that the probability of Chip losing is 1 / (1 + 6) = 1 / 7. Therefore, the probability of Chip winning is 1 - 1 / 7 = 6 / 7.

Question 13

Solve the problem.
-The odds in favor of Trudy beating her friend in a round of golf are 1 : 7. Find the probability that Trudy will lose. 
A) $ \frac{1}{8} $
B) $ \frac{7}{9} $
C) $ \frac{1}{10} $
D) $ \frac{7}{8} $

Accepted Answer

The odds in favor of Trudy winning are 1:7, meaning for every 1 time she wins, she loses 7 times. The total outcomes are 1 + 7 = 8. The probability of her losing is the number of times she loses divided by the total outcomes, which is $ \frac{7}{8} $.

Question 14

Solve the problem.
-The results of a medical test show that of 75 people selected at random who were given the test, 3 Tested positive and 72 tested negative. Determine the odds in favor of a person selected at random Testing positive on the test.
A) 1 : 24
B) 24 : 1
C)25: 1
D)1 : 25

Accepted Answer

The odds in favor of a person testing positive are calculated by comparing the number of positive outcomes to the number of negative outcomes. With 3 testing positive and 72 testing negative, the odds in favor are 3:72, which simplifies to 1:24.

Question 15

Solve the problem.
-Suppose you buy 1 ticket for $1 out of a lottery of 1,000 tickets where the prize for the one winning Ticket is to be $500. What are your expected winnings?
A) -$0.40
B) -$0.50
C) -$1.00
D) $0.00

Accepted Answer

The expected winnings can be calculated by multiplying the probability of winning with the amount won and adding it to the probability of losing multiplied by the amount lost. The probability of winning is 1/1000, and the prize is $500, so the expected winnings from winning are (1/1000)*$500 = $0.50. The probability of losing is 999/1000, and since you spend $1 to buy a ticket, the expected loss is (999/1000)*(-$1) = -$0.999. Adding these together, the expected winnings are $0.50 - $0.999 = -$0.499, which rounds to -$0.50.

Question 16

Solve the problem.
-The odds in favor of Carl beating his friend in a round of golf are 8 : 5. Find the probability that Carl  Will lose.
A) $ \frac{1}{3} $
B) $ \frac{5}{8} $
C) $ \frac{5}{13} $
D) $ \frac{8}{13} $

Accepted Answer

The odds in favor of Carl winning are 8:5, meaning for every 8 times Carl wins, he loses 5 times. The total outcomes are 8 wins + 5 losses = 13. The probability of losing is the number of losing outcomes over the total outcomes, which is $ \frac{5}{13} $.

Question 17

Solve the problem.
-The chart shows winnings, in dollars, for the 10 highest-rated FASTCAR drivers for last driving Season. $$\begin{array} { l | l } 
\text { Driver } & \text { Winnings } \
\hline \text { Rick Bobby } & \$ 6,320,849 \
\text { Maverick St. Joseph } & \$ 5,198,600 \
\text { Johnny Wright } & \$ 2,140,478 \
\text { Jay Smith } & \$ 4,606,127 \
\text { William Rock } & \$ 2,951,951 \
\text { Bob Ricky } & \$ 4,020,078 \
\text { Jimmy Novak } & \$ 4,420,069 \
\text { Tommy Keefe } & \$ 5,501,450 \
\text { Tyler Jones } & \$ 3,153,196
\end{array}$$
If one of the drivers listed in the chart is selected at random, determine the odds against the driver Earning more than $4 million last season.
A) 9 : 3
B)3 : 6
C)6: 3
D)3 : 9

Accepted Answer

The answer of Solve the problem.
-The chart shows winnings, in...

Question 18

Solve the problem.
-The odds against Carl beating his friend in a round of golf are 8 : 5. Find the probability that Carl Will lose. 
A) $ \frac{4}{7} $
B) $ \frac{5}{8} $
C) $ \frac{8}{13} $
D) $ \frac{5}{13} $

Accepted Answer

The odds against Carl winning are 8:5, meaning for every 8 times he loses, he wins 5 times. The total outcomes are 8 (losses) + 5 (wins) = 13. The probability of losing is the number of losing outcomes over the total outcomes, which is $ \frac{8}{13} $.

Question 19

Solve the problem.
-The odds against Carl beating his friend in a round of golf are 9 : 5. Find the probability that Carl Will beat his friend. 
A) $ \frac{9}{14} $
B) $ \frac{1}{3} $
C) $ \frac{5}{14} $
D) $ \frac{5}{9} $

Accepted Answer

The odds against Carl are 9:5, meaning for every 9 times he doesn't win, he wins 5 times. The probability is the ratio of wins to total attempts, so $ \frac{5}{9+5} = \frac{5}{14} $.

Question 20

Solve the problem.
-If the probability that an identified hurricane will make a direct hit on a certain stretch of beach is 0.02, what are the odds against a direct hit?
A) 1 to 50
B) 50 to 1
C)49to 1
D)48 to 1

Accepted Answer

The probability of a direct hit is 0.02, so the probability against a direct hit is 1 - 0.02 = 0.98. The odds against a direct hit are 0.98/0.02 = 49 to 1.

Quiz 11: Probability

Solve the problem. -The odds in favor of Jerome beating his friend in a round of golf are 1 : 7. Find the probability that Jerome will beat his friend.

Solve the problem. -In a certain town, 25% of people commute to work by bicycle. If a person is selected randomly From the town, what are the odds against selecting someone who commutes by bicycle?

Solve the problem. -The odds against Muffy beating her friend in a round of golf are 1 : 6. Find the probability that Muffy will lose.

Solve the problem. -The odds in favor of a horse winning a race are posted as 8 : 7. Find the probability that the horse Will lose the race.

Solve the problem. -The odds in favor of a horse winning a race are posted as 4 : 3. Find the probability that the horse Will win the race.

Solve the problem. -The odds in favor of Carl beating his friend in a round of golf are 9 : 2. Find the probability that Carl will beat his friend.

Solve the problem. -In a certain town, 5% of people commute to work by bicycle. If a person is selected randomly from The town, what are the odds in favor of selecting someone who commutes by bicycle?

Solve the problem. -If it has been determined that the probability of an earthquake occurring on a certain day in a Certain area is 0.01, what are the odds against an earthquake?

Find the probability. -Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed Well. Two are drawn. What are the odds in favor of the sum of the numbers on the two selected Slips is not 6?

Solve the problem. -If it has been determined that the probability of an earthquake occurring on a certain day in a Certain area is 0.01, what are the odds in favor of an earthquake?

Solve the problem. -If the probability that an identified hurricane will make a direct hit on a certain stretch of beach is 0.04, what are the odds in favor of a direct hit?

Solve the problem. -The odds against Chip beating his friend in a round of golf are 1 : 6. Find the probability that Chip Will beat his friend.

Solve the problem. -The odds in favor of Trudy beating her friend in a round of golf are 1 : 7. Find the probability that Trudy will lose.

Solve the problem. -The results of a medical test show that of 75 people selected at random who were given the test, 3 Tested positive and 72 tested negative. Determine the odds in favor of a person selected at random Testing positive on the test.

Solve the problem. -Suppose you buy 1 ticket for $1 out of a lottery of 1,000 tickets where the prize for the one winning Ticket is to be $500. What are your expected winnings?

Solve the problem. -The odds in favor of Carl beating his friend in a round of golf are 8 : 5. Find the probability that Carl Will lose.

Solve the problem. -The odds against Carl beating his friend in a round of golf are 8 : 5. Find the probability that Carl Will lose.

Solve the problem. -The odds against Carl beating his friend in a round of golf are 9 : 5. Find the probability that Carl Will beat his friend.

Solve the problem. -If the probability that an identified hurricane will make a direct hit on a certain stretch of beach is 0.02, what are the odds against a direct hit?