The Data in the Table Represent the Amount of Pressure

The data in the table represent the amount of pressure (psi) exerted by a stamping machine (x) , and the amount of scrap brass shavings (in pounds) that are collected from the machine each hour (y) .
Also shown below are the outputs from two different statistical technologies (TI-83/84 Calculator and Excel) . A scatterplot of the data confirms that there is a linear association. Report the equation for predicting scrap brass shavings using words such as scrap, not x and y. State the slope and
Intercept of the prediction equation. Round all calculations to the nearest thousandth. $\begin{array}{|c|r|}\hline x & y \\\hline 2.00 & 2.30 \\\hline 7.80 & 15.14 \\\hline 14.51 & 28.65 \\\hline 2.80 & 4.15 \\\hline 4.01 & 6.35 \\\hline 6.21 & 10.52 \\\hline 11.84 & 24.05 \\\hline 5.11 & 8.75 \\\hline 11.67 & 22.22 \\\hline 8.70 & 17.02 \\\hline\end{array}$

T-Test
$\begin{array} { l } y = a + b x \\a = - 2.018775528 \\b = 2.134464237 \\r ^ { 2 } = .996074796 \\r = .998035467\end{array}$

$\begin{array}{|l|r|}\hline & \multicolumn{1}{|c|}{\text { Coefficients }} \\\hline \text { Intercept } & -2.018775528 \\\hline \text { X Variable 1 } & 2.134464237 \\\hline\end{array}$

A) scrap $= - 2.019 + 2.134$ (pressure) ; slope $= - 2.019$ and the intercept is $2.134$ .
B) scrap $= 2.134 - 2.019$ (pressure) ; slope $= - 2.019$ and the intercept is $2.134$ .
C) scrap $= - 2.019 + 2.134$ (pressure) ; slope $= 2.134$ and the intercept is $- 2.019$ .
D) scrap $= 2.134 - 2.019$ (pressure) ; slope $= 2.134$ and the intercept is $- 2.019$ .