Solve the equation.
-$$9^{7 x + 3} = 27$$
A) $\left\{ - \frac { 3 } { 7 } \right\}$
B) $\left\{ \frac { 3 } { 14 } \right\}$
C) $\left\{ - \frac { 3 } { 14 } \right\}$
D) $\left\{ \frac { 3 } { 7 } \right\}$

Question

Quizplus · Accepted Answer

To solve the equation, express both sides with the same base: $9 = 3^2$ and $27 = 3^3$. Thus, $9^{7x+3} = (3^2)^{7x+3} = 3^{14x+6}$. Set the exponents equal: $14x + 6 = 3$. Solving for $x$, we get $14x = -3$, so $x = -\frac{3}{14}$.

Solve the Equation 97x+3=279^{7 x + 3} = 2797x+3=27 A) {−37}\left\{ - \frac { 3 } { 7 } \right\}{−73​}

Solve the Equation $9^{7 x + 3} = 27$ A) $\left\{ - \frac { 3 } { 7 } \right\}$