Solve the equation.
-$\log ( 4 x ) = \log 3 + \log ( x - 2 )$
A) $\left\{ \frac { 1 } { 3 } \right\}$
B) $\{ 6 \rangle$
C) $\left\{ - \frac { 6 } { 7 } \right\}$
D) $\{ - 6 \rangle$

Question

Quizplus · Accepted Answer

The Answer of Solve the equation.
-$\log ( 4 x ) = \log 3 + \log ( x - 2 )$
A) $\left\{ \frac { 1 } { 3 } \right\}$
B) $\{ 6 \rangle$
C) $\left\{ - \frac { 6 } { 7 } \right\}$
D) $\{ - 6 \rangle$

Solve the Equation log⁡(4x)=log⁡3+log⁡(x−2)\log ( 4 x ) = \log 3 + \log ( x - 2 )log(4x)=log3+log(x−2)

Solve the Equation $\log ( 4 x ) = \log 3 + \log ( x - 2 )$