Solve the equation.
-$\log _ { 8 } ( 4 x + 2 ) = \log _ { 8 } ( 4 x + 5 )$
A) $\{ 3 \}$
B) $\{ 0 \}$
C) $\left\{ \frac { 7 } { 3 } \right\}$
D) $\varnothing$

Name: Solve the equation. -$\log _ { 8 } ( 4 x + 2 ) = \log _ { 8 } ( 4 x + 5 )$ A) $\{ 3 \}$ B) $\{ 0 \}$ C) $\left\{ \frac { 7 } { 3 } \right\}$ D) $\varnothing$
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Question

Quizplus · Accepted Answer

For two logarithms to be equal, their arguments must be equal. However, setting $4x + 2 = 4x + 5$ leads to a contradiction (2 ≠ 5), indicating no solution exists.

Solve the Equation log⁡8(4x+2)=log⁡8(4x+5)\log _ { 8 } ( 4 x + 2 ) = \log _ { 8 } ( 4 x + 5 )log8​(4x+2)=log8​(4x+5)

Solve the Equation $\log _ { 8 } ( 4 x + 2 ) = \log _ { 8 } ( 4 x + 5 )$