Convert the point whose polar coordinates are $( \sqrt { 3 } , \pi / 6 )$ to rectangular coordinates
A) $\left( \frac { 3 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)$

B) $\left( \frac { 3 } { 2 } , \frac { 1 } { 2 } \right)$

C) $( 3 , \sqrt { 3 } )$

D) $( \sqrt { 3 } , \pi / 6 )$

E) $\left( \frac { 2 } { 3 } , \frac { \sqrt { 2 } } { 2 } \right)$

Question

Convert the point whose polar coordinates are $( \sqrt { 3 } , \pi / 6 )$ to rectangular coordinates
A) $\left( \frac { 3 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)$

B) $\left( \frac { 3 } { 2 } , \frac { 1 } { 2 } \right)$

C) $( 3 , \sqrt { 3 } )$

D) $( \sqrt { 3 } , \pi / 6 )$

E) $\left( \frac { 2 } { 3 } , \frac { \sqrt { 2 } } { 2 } \right)$

Quizplus · Accepted Answer

Using the formula $x=r\cos	heta$ and $y=r\sin	heta$, we have $x=\sqrt{3}\cos\frac{\pi}{6}=\frac{3}{2}$ and $y=\sqrt{3}\sin\frac{\pi}{6}=\frac{\sqrt{3}}{2}$, which gives the rectangular coordinates $\left(\frac{3}{2},\frac{\sqrt{3}}{2}ight)$, so the answer is $\boxed{	extbf{(A)}}$.

Convert the Point Whose Polar Coordinates Are (3,π/6)( \sqrt { 3 } , \pi / 6 )(3​,π/6)

Convert the Point Whose Polar Coordinates Are $( \sqrt { 3 } , \pi / 6 )$