Convert the equation to polar form. $x ^ { 2 } + y ^ { 2 } = 16$
A) $r^ { 2 } = 4$
B) $4 r= \cos \theta + \sin \theta$
C) $y = 4 \cos \theta + 4 \sin \theta$
D) $r = 4$
E)none of these

Question

Quizplus · Accepted Answer

To convert to polar form, we substitute $x=r\cos	heta$ and $y=r\sin	heta$:
$$r^2=r^2\cos^2	heta+r^2\sin^2	heta=16\implies r=4$$
So, the polar form is $\boxed{\gamma=4}$.

Convert the Equation to Polar Form x2+y2=16x ^ { 2 } + y ^ { 2 } = 16x2+y2=16

Convert the Equation to Polar Form $x ^ { 2 } + y ^ { 2 } = 16$