The synthesis of the pesticide thionyl chloride (OSCl₂) proceeds according to:
SO₃( g ) + SCl₂( l ) OSCl₂( l ) + SO₂( g )
If Δ G⁰ = − 106 kJ/mol for this reaction at 298K, what is the K_eq at this temperature? Recall: R = 8.314 J mol^{− 1} K^{− 1}.

Question

The synthesis of the pesticide thionyl chloride (OSCl₂) proceeds according to:
SO₃( g ) + SCl₂( l )

The synthesis of the pesticide thionyl chloride (OSCl<sub>2</sub>) proceeds according to: SO<sub>3</sub>( g ) + SCl<sub>2</sub>( l ) OSCl<sub>2</sub>( l ) + SO<sub>2</sub>( g ) <sub> </sub> If Δ G<sup>0</sup> = − 106 kJ/mol for this reaction at 298K, what is the K<sub>eq</sub> at this temperature? Recall: R = 8.314 J mol<sup> − 1</sup> K<sup> − 1</sup>. A) 7.21 × 10<sup>12</sup> B) 3.50 × 10<sup>14</sup> C) 3.81 × 10<sup>18</sup> D) 1.19 × 10<sup>20</sup>

OSCl₂( l ) + SO₂( g )
If Δ G⁰ = − 106 kJ/mol for this reaction at 298K, what is the K_eq at this temperature? Recall: R = 8.314 J mol^{− 1} K^{− 1}.

Quizplus · Accepted Answer

The Answer of The synthesis of the pesticide thionyl chloride (OSCl₂) proceeds according to: SO₃( g ) + SCl₂( l ) OSCl₂( l ) + SO₂( g ) If Δ G⁰ = − 106 kJ/mol for this reaction at 298K, what is the K_eq at this temperature? Recall: R = 8.314 J mol^{− 1} K^{− 1}.

The Synthesis of the Pesticide Thionyl Chloride (OSCl2) Proceeds According

The Synthesis of the Pesticide Thionyl Chloride (OSCl₂) Proceeds According