Write the first five terms of the sequence $a _ { n } = - \frac { 3 } { n + 4 }$ . Assume that n begins with 1.
A) $a _ { 1 } = \frac { 3 } { 5 } , a _ { 2 } = - \frac { 1 } { 2 } , a _ { 3 } = \frac { 3 } { 7 } , a _ { 4 } = - \frac { 3 } { 8 } , a _ { 5 } = \frac { 1 } { 3 }$
B) $a _ { 1 } = \frac { 3 } { 4 } , a _ { 2 } = - \frac { 3 } { 5 } a _ { 3 } = \frac { 1 } { 2 } , a _ { 4 } = \frac { 3 } { 7 } , a _ { 5 } = \frac { 3 } { 8 }$
C) $a _ { 1 } = \frac { 3 } { 4 } , a _ { 2 } = \frac { 3 } { 5 } a _ { 3 } = \frac { 1 } { 2 } , a _ { 4 } = \frac { 3 } { 7 } , a _ { 5 } = \frac { 3 } { 8 }$
D) $a _ { 1 } = - \frac { 3 } { 4 } , a _ { 2 } = \frac { 3 } { 5 } a _ { 3 } = - \frac { 1 } { 2 } , a _ { 4 } = \frac { 3 } { 7 } , a _ { 5 } = - \frac { 3 } { 8 }$
E) $a _ { 1 } = - \frac { 3 } { 5 } , a _ { 2 } = - \frac { 1 } { 2 } , a _ { 3 } = - \frac { 3 } { 7 } , a _ { 4 } = - \frac { 3 } { 8 } , a _ { 5 } = - \frac { 1 } { 3 }$

Question

Quizplus · Accepted Answer

The sequence $a_n = - \frac{3}{n + 4}$ generates terms by substituting $n$ values starting from 1. Calculating the first five terms with $n = 1, 2, 3, 4, 5$ gives $a_1 = -\frac{3}{5}, a_2 = -\frac{1}{2}, a_3 = -\frac{3}{7}, a_4 = -\frac{3}{8}, a_5 = -\frac{1}{3}$, which matches option E.

Write the First Five Terms of the Sequence an=−3n+4a _ { n } = - \frac { 3 } { n + 4 }an​=−n+43​

Write the First Five Terms of the Sequence $a _ { n } = - \frac { 3 } { n + 4 }$