Find $a _ { 8 }$ of the sequence $a _ { n } = \frac { n ^ { 2 } - 7 } { ( n - 2 ) ! }$ .
A) $a _ { 8 } = \frac { 32 } { 361 }$
B) $a _ { 8 } = - \frac { 32 } { 361 }$
C) $a _ { 8 } = - \frac { 19 } { 1680 }$
D) $a _ { 8 } = \frac { 19 } { 1680 }$
E) $a _ { 8 } = \frac { 19 } { 240 }$

Question

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The Answer of Find $a _ { 8 }$ of the sequence $a _ { n } = \frac { n ^ { 2 } - 7 } { ( n - 2 ) ! }$ .
A) $a _ { 8 } = \frac { 32 } { 361 }$
B) $a _ { 8 } = - \frac { 32 } { 361 }$
C) $a _ { 8 } = - \frac { 19 } { 1680 }$
D) $a _ { 8 } = \frac { 19 } { 1680 }$
E) $a _ { 8 } = \frac { 19 } { 240 }$

Find a8a _ { 8 }a8​ Of the Sequence an=n2−7(n−2)!a _ { n } = \frac { n ^ { 2 } - 7 } { ( n - 2 ) ! }an​=(n−2)!n2−7​

Find $a _ { 8 }$ Of the Sequence $a _ { n } = \frac { n ^ { 2 } - 7 } { ( n - 2 ) ! }$