A group of 52 participants was divided equally into 4 groups. A Tukey HSD produced a value that led to the conclusion that Mean 1 was significantly larger than Mean 2, p

Question

A group of 52 participants was divided equally into 4 groups. A Tukey HSD produced a value that led to the conclusion that Mean 1 was significantly larger than Mean 2, p < .05. Which of the following situations would lead to such a conclusion?
A) $\bar { X } _ { 1 } = 10.9 , \bar { X } _ { 2 } = 6.1 , M S _ { \text {error } } = 20$
B) $\bar { X } _ { 1 } = 152 , \bar { X } _ { 2 } = 140 ; M S _ { \text {error } } = 130$
C) both of the descriptive alternatives are correct
D) neither of the descriptive alternatives is correct.

Quizplus · Accepted Answer

Both A and B describe situations where Mean 1 is significantly larger than Mean 2, as indicated by the Tukey HSD test results. The specific values of the means and the mean square error (MS_error) are not directly relevant to the conclusion of significance; what matters is the statistical test's outcome.

A Group of 52 Participants Was Divided Equally into 4 Xˉ1=10.9,Xˉ2=6.1,MSerror =20\bar { X } _ { 1 } = 10.9 , \bar { X } _ { 2 } = 6.1 , M S _ { \text {error } } = 20Xˉ1​=10.9,Xˉ2​=6.1,MSerror ​=20

A Group of 52 Participants Was Divided Equally into 4 $\bar { X } _ { 1 } = 10.9 , \bar { X } _ { 2 } = 6.1 , M S _ { \text {error } } = 20$