A Group of 50 Participants Was Divided Equally into 5 $\bar { X } _ { 1 } = 13 , \bar { X } _ { 2 } = 5 , M S _ { \text {error } } = 36$

A group of 50 participants was divided equally into 5 groups. A Tukey HSD produced a value that led to the conclusion that Mean 1 was significantly larger than Mean 2, p < .05. Which of the following situations would lead to such a conclusion?

A) $\bar { X } _ { 1 } = 13 , \bar { X } _ { 2 } = 5 , M S _ { \text {error } } = 36$
B) $\bar { X } _ { 1 } = 54 , \bar { X } _ { 2 } = 36 , M S _ { \text {error } } = 240$
C) $\bar { X } _ { 1 } = 5 \bar { X } _ { 2 } = 2 , M S _ { \text {error } } = 40$
D) none of the other alternatives are correct.