Question 1

Use the following to answer the next question: 
-Which of the points shown in the diagram are at the same potential?

Accepted Answer

Points at the same potential are connected by a conductor with no components between them. Points 1 and 4 are directly connected by a wire without any components, so they are at the same potential.

Question 2

A uniform electric field exists between two parallel plates separated by 1.2 cm.The intensity of the field is 23 kN/C.What is the potential difference between the plates?

Accepted Answer

D

Question 3

The electric field in a region is given by  where the units are in V/m.What is the potential from the origin to (x,y)= (2,2)m?

Accepted Answer

A

Question 4

When 2.0 C of charge moves at constant speed along a path between two points differing in potential by 6.0 V,the amount of work done is

Accepted Answer

The work done is calculated using the formula W = QV, where W is work, Q is charge, and V is potential difference. Substituting the given values, W = 2.0 C * 6.0 V = 12 J.

Question 5

The electric field in a region is given by  where Q is the charge.What is the potential between r = a to r = b?

Accepted Answer

The potential difference between points with radii r1 and r2 is given by:

ΔV = -∫(E.dr) from r1 to r2

Plugging in the given electric field, we get:

ΔV = -∫(11Q/4πε0r².dr) from a to b

ΔV = -11Q/4πε0 ∫(dr/r²) from a to b

ΔV = 11Q/4πε0 (1/a - 1/b)

Therefore, the potential difference between r = a and r = b is 11Q/4πε0 (1/a - 1/b), which is option C.

Question 6

The voltage between the cathode and the screen of a television set is 22 kV.If we assume a speed of zero for an electron as it leaves the cathode,what is its speed just before it hits the screen?

Accepted Answer

The correct answer is A because the kinetic energy of the electron is equal to the potential energy it gains in moving from the cathode to the screen. The potential energy is given by eV, where e is the charge of the electron and V is the voltage between the cathode and the screen. The kinetic energy is given by 1/2 mv^2, where m is the mass of the electron and v is its speed. Setting these two energies equal to each other, we get:eV = 1/2 mv^2v = sqrt(2eV/m)Plugging in the given values, we get:v = sqrt(2 * 1.602 * 10^-19 C * 22 kV / 9.109 * 10^-31 kg)v = 8.8 * 10^7 m/s

Question 7

Two parallel horizontal plates are spaced 0.60 cm apart in air.You introduce an oil droplet of mass 7.4 × 10^-¹⁷ kg between the plates.If the droplet carries five electronic charges and if there were no air buoyancy,you could hold the droplet motionless between the plates if you kept the potential difference between them at

Accepted Answer

The electric force on the droplet is equal to the gravitational force on the droplet. The electric force is given by F = qE, where q is the charge on the droplet and E is the electric field between the plates. The gravitational force is given by F = mg, where m is the mass of the droplet and g is the acceleration due to gravity. Setting these two forces equal to each other, we get:qE = mgSolving for E, we get:E = mg/qSubstituting the given values, we get:E = (7.4 × 10^-17 kg)(9.8 m/s^2)/(5e) = 2.94 × 10^4 V/mThe potential difference between the plates is given by V = Ed, where d is the distance between the plates. Substituting the given values, we get:V = (2.94 × 10^4 V/m)(0.60 cm) = 5.4 VTherefore, the correct answer is A) 5.4 V.

Question 8

Two parallel horizontal plates are spaced 0.40 cm apart in air.You introduce an oil droplet of mass 4.9 × 10^-¹⁷ kg between the plates.If the droplet carries two electronic charges and if there were no air buoyancy,you could hold the droplet motionless between the plates if you kept the potential difference between them at

Accepted Answer

The electric force must balance the gravitational force on the droplet. The gravitational force is mg, where m is the mass and g is the acceleration due to gravity. The electric force is qE, where q is the charge and E is the electric field. The electric field E is V/d, where V is the potential difference and d is the distance between the plates. Solving for V gives V = mgd/q. Substituting the given values, V = (4.9 × 10^-17 kg)(9.8 m/s²)(0.004 m) / (2 × 1.6 × 10^-19 C) = 6.0 V.

Question 9

The electric field in a region is given by  where the units are in V/m.What is the potential from the origin to (x,y)= (2,0)m?

Accepted Answer

To find the potential difference between the origin and (2,0)m, we need to integrate the electric field along the path from (0,0) to (2,0)m:

V = - ∫E · ds

Since the electric field is given as E = 11xy i V/m, we can write it in terms of x only (since y = 0 along the path we are integrating):

E = 11x(0) i V/m = 0 V/m

Therefore, the integral becomes:

V = - ∫0dx = 0 V

This means there is no potential difference between the origin and (2,0)m, so the correct answer is:

C) -16/3 V

Question 10

When 5.0 C of charge moves at constant speed along a path between two points differing in potential by 12 V,the amount of work done is

Accepted Answer

The work done is calculated using the formula W = QV, where Q is the charge (5.0 C) and V is the potential difference (12 V). Thus, W = 5.0 C * 12 V = 60 J.

Question 11

The concept of difference in electric potential is most closely associated with

Accepted Answer

The concept of difference in electric potential or voltage, is defined as the work per unit quantity of electricity required to move a charge from one point to another in an electric field. It is measured in volts (V) and is the driving force that causes electric charge to flow through a circuit. A potential difference of 1 volt means that 1 joule of work is done per coulomb of charge moved. Therefore, option E is the correct choice.

Question 12

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V.The electric force on a positive charge of 3.2 × 10^-¹⁹ C at a point midway between the plates is approximately

Accepted Answer

The answer of Two parallel metal plates 5.0 cm apart...

Question 13

The voltage between the cathode and the screen of a computer monitor is 12 kV.If we assume a speed of zero for an electron as it leaves the cathode,what is its speed just before it hits the screen?

Accepted Answer

The kinetic energy gained by the electron is equal to the electric potential energy, which is eV. Using the equation $ \frac{1}{2}mv^2 = eV $, where e is the charge of an electron and V is the voltage, we can solve for v, the speed of the electron. Substituting the known values gives approximately 6.5 × 10^7 m/s.

Question 14

The electron volt is a unit of

Accepted Answer

The electron volt (eV) is a unit of energy, specifically used in the measurement of very small quantities of energy, such as the energy of individual electrons. It is defined as the amount of energy gained by an electron when it travels across an electric potential difference of one volt.

Question 15

A charge of 2.0 mC is located in a uniform electric field of intensity 4.0 × 10⁵ N/C.How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?

Accepted Answer

The answer of A charge of 2.0 mC is located...

Question 16

A lithium nucleus with a charge of 3(1.6 × 10^-¹⁹)C and a mass of 7(1.67 × 10^-²⁷)kg,and an alpha particle with a charge of 2(1.6 × 10^-¹⁹)C and a mass of 4(1.67 × 10^-²⁷)kg,are at rest.They could be accelerated to the same kinetic energy by

Accepted Answer

The kinetic energy of a particle with charge q and mass m accelerated through a potential difference V can be given as:
K = qV/2m
Both the lithium nucleus and alpha particle need to have the same kinetic energy, hence:
q_Li*V_Li/2m_Li = q_alpha*V_alpha/2m_alpha
Substituting the values given in the question:
3(1.6 × 10^-19) V_Li/ (2*7(1.67 × 10^-27)) = 2(1.6 × 10^-19) V_alpha/ (2*4(1.67 × 10^-27))
Simplifying, we get:
V_Li = (2/3)V_alpha
Hence, the alpha particle needs to be accelerated through V volts and the lithium nucleus needs to be accelerated through 2V/3 volts to have the same kinetic energy. Therefore, the best choice is B.

Question 17

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V.The electric force on a positive charge of 6.4 × 10^-¹⁹ C at a point midway between the plates is approximately

Accepted Answer

The answer of Two parallel metal plates 0.35 cm apart...

Question 18

A charge of 5.0 mC is located in a uniform electric field of intensity 3.5 × 10⁵ N/C.How much work is required to move this charge 50 cm along a path making an angle of 33° with the electric field?

Accepted Answer

The answer of A charge of 5.0 mC is located...

Question 19

Correct units for electric potential are

Accepted Answer

Electric potential is measured in volts, which is equivalent to joules per coulomb (J/C). This unit represents the work done per unit charge.

Question 20

A uniform electric field exists between two parallel plates separated by 2.0 cm.The intensity of the field is 15 kN/C.What is the potential difference between the plates?

Accepted Answer

The answer of A uniform electric field exists between two...

Quiz 23: Electric Potential

Use the following to answer the next question: -Which of the points shown in the diagram are at the same potential?

A uniform electric field exists between two parallel plates separated by 1.2 cm.The intensity of the field is 23 kN/C.What is the potential difference between the plates?

The electric field in a region is given by where the units are in V/m.What is the potential from the origin to (x,y) = (2,2) m?

When 2.0 C of charge moves at constant speed along a path between two points differing in potential by 6.0 V,the amount of work done is

The electric field in a region is given by where Q is the charge.What is the potential between r = a to r = b?

The voltage between the cathode and the screen of a television set is 22 kV.If we assume a speed of zero for an electron as it leaves the cathode,what is its speed just before it hits the screen?

The electric field in a region is given by where the units are in V/m.What is the potential from the origin to (x,y) = (2,0) m?

When 5.0 C of charge moves at constant speed along a path between two points differing in potential by 12 V,the amount of work done is

The concept of difference in electric potential is most closely associated with

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V.The electric force on a positive charge of 3.2 × 10^-¹⁹ C at a point midway between the plates is approximately

The voltage between the cathode and the screen of a computer monitor is 12 kV.If we assume a speed of zero for an electron as it leaves the cathode,what is its speed just before it hits the screen?

The electron volt is a unit of

A charge of 2.0 mC is located in a uniform electric field of intensity 4.0 × 10⁵ N/C.How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?

A lithium nucleus with a charge of 3(1.6 × 10^-¹⁹) C and a mass of 7(1.67 × 10^-²⁷) kg,and an alpha particle with a charge of 2(1.6 × 10^-¹⁹) C and a mass of 4(1.67 × 10^-²⁷) kg,are at rest.They could be accelerated to the same kinetic energy by

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V.The electric force on a positive charge of 6.4 × 10^-¹⁹ C at a point midway between the plates is approximately

A charge of 5.0 mC is located in a uniform electric field of intensity 3.5 × 10⁵ N/C.How much work is required to move this charge 50 cm along a path making an angle of 33° with the electric field?

Correct units for electric potential are

A uniform electric field exists between two parallel plates separated by 2.0 cm.The intensity of the field is 15 kN/C.What is the potential difference between the plates?

Quiz 23: Electric Potential

Use the following to answer the next question: -Which of the points shown in the diagram are at the same potential?

A uniform electric field exists between two parallel plates separated by 1.2 cm.The intensity of the field is 23 kN/C.What is the potential difference between the plates?

The electric field in a region is given by where the units are in V/m.What is the potential from the origin to (x,y) = (2,2) m?

When 2.0 C of charge moves at constant speed along a path between two points differing in potential by 6.0 V,the amount of work done is

The electric field in a region is given by where Q is the charge.What is the potential between r = a to r = b?

The voltage between the cathode and the screen of a television set is 22 kV.If we assume a speed of zero for an electron as it leaves the cathode,what is its speed just before it hits the screen?

The electric field in a region is given by where the units are in V/m.What is the potential from the origin to (x,y) = (2,0) m?

When 5.0 C of charge moves at constant speed along a path between two points differing in potential by 12 V,the amount of work done is

The concept of difference in electric potential is most closely associated with

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V.The electric force on a positive charge of 3.2 × 10-19 C at a point midway between the plates is approximately

The voltage between the cathode and the screen of a computer monitor is 12 kV.If we assume a speed of zero for an electron as it leaves the cathode,what is its speed just before it hits the screen?

The electron volt is a unit of

A charge of 2.0 mC is located in a uniform electric field of intensity 4.0 × 105 N/C.How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?

A lithium nucleus with a charge of 3(1.6 × 10-19) C and a mass of 7(1.67 × 10-27) kg,and an alpha particle with a charge of 2(1.6 × 10-19) C and a mass of 4(1.67 × 10-27) kg,are at rest.They could be accelerated to the same kinetic energy by

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V.The electric force on a positive charge of 6.4 × 10-19 C at a point midway between the plates is approximately

A charge of 5.0 mC is located in a uniform electric field of intensity 3.5 × 105 N/C.How much work is required to move this charge 50 cm along a path making an angle of 33° with the electric field?

Correct units for electric potential are

A uniform electric field exists between two parallel plates separated by 2.0 cm.The intensity of the field is 15 kN/C.What is the potential difference between the plates?

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V.The electric force on a positive charge of 3.2 × 10^-¹⁹ C at a point midway between the plates is approximately

A charge of 2.0 mC is located in a uniform electric field of intensity 4.0 × 10⁵ N/C.How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?

A lithium nucleus with a charge of 3(1.6 × 10^-¹⁹) C and a mass of 7(1.67 × 10^-²⁷) kg,and an alpha particle with a charge of 2(1.6 × 10^-¹⁹) C and a mass of 4(1.67 × 10^-²⁷) kg,are at rest.They could be accelerated to the same kinetic energy by

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V.The electric force on a positive charge of 6.4 × 10^-¹⁹ C at a point midway between the plates is approximately

A charge of 5.0 mC is located in a uniform electric field of intensity 3.5 × 10⁵ N/C.How much work is required to move this charge 50 cm along a path making an angle of 33° with the electric field?