What is the maximum hydroxide-ion concentration that a 0.019 M MgCl₂ solution could have without causing the precipitation of Mg(OH)₂? For Mg(OH)₂,K_sp = 1.8 × 10^-11. A) 4.2 × 10^-6 B) 1.7 × 10^-4 C) 1.2 × 10^-8 D) 9.5 × 10^-9 E) 3.1 × 10^-5

Question

Quizplus · Accepted Answer

The solubility product expression for Mg(OH)₂ is Ksp = [Mg²⁺][OH⁻]². Given Ksp = 1.8 × 10⁻¹¹ and [Mg²⁺] = 0.019 M, solve for [OH⁻]: [OH⁻] = √(Ksp / [Mg²⁺]) = √(1.8 × 10⁻¹¹ / 0.019) = 3.1 × 10⁻⁵ M.

What Is the Maximum Hydroxide-Ion Concentration That a 0