When 0.20 mole HF is dissolved in water to a volume of 1.00 L,5.8% of the HF dissociates to form F-(aq) .What is the equilibrium constant for the reaction? HF(aq) + H2O( 
) 
F-(aq) + H3O+(aq)
A) 1.3 × 10-4
B) 7.1 × 10-4
C) 1.2 × 10-2
D) 1.7 × 10-2
E) 6.2 × 10-2
Correct Answer:
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