The thermochemical equation for the combustion of methanol is given below. CH₃OH( ) + 3/2 O₂(g) → CO₂(g) + 2 H ₂O(g)
Δ_rH° = -638.7 kJ/mol-rxn
What is the enthalpy change for the combustion of 8.59 g of CH₃OH?

Question

The thermochemical equation for the combustion of methanol is given below. CH₃OH(

The thermochemical equation for the combustion of methanol is given below. CH<sub>3</sub>OH( ) + 3/2 O<sub>2</sub>(g) → CO<sub>2</sub>(g) + 2 H <sub>2</sub>O(g) Δ<sub>r</sub>H° = -638.7 kJ/mol-rxn What is the enthalpy change for the combustion of 8.59 g of CH<sub>3</sub>OH? A) -171 kJ B) -19.9 kJ C) -2.38 × 10<sup>3</sup> kJ D) -5.49 × 10<sup>3</sup> kJ E) -1.76 × 10<sup>6</sup> kJ

) + 3/2 O₂(g) → CO₂(g) + 2 H ₂O(g)
Δ_rH° = -638.7 kJ/mol-rxn
What is the enthalpy change for the combustion of 8.59 g of CH₃OH?

Quizplus · Accepted Answer

The Answer of The thermochemical equation for the combustion of methanol is given below. CH₃OH( )+ 3/2 O₂(g)→ CO₂(g)+ 2 H ₂O(g) Δ_rH° = -638.7 kJ/mol-rxn What is the enthalpy change for the combustion of 8.59 g of CH₃OH?

The Thermochemical Equation for the Combustion of Methanol Is Given