Consider the following interaction between a protein and its ligand: [P] + [L] $\harr$[PL]. If [L] = 5 mM, [P] = 3 mM, and [PL] = 2 mM, what is the dissociation constant?
A) 7.5 mM
B) 15 mM
C) 0.133 mM
D) 0.4 mM

Question

Consider the following interaction between a protein and its ligand: [P] + [L]   $\harr$[PL]. If [L] = 5 mM, [P] = 3 mM, and [PL] = 2 mM, what is the dissociation constant?
A) 7.5 mM
B) 15 mM
C) 0.133 mM
D) 0.4 mM

Quizplus · Accepted Answer

The dissociation constant (Kd) is calculated using the formula Kd = [P][L]/[PL]. Substituting the given values: Kd = (3 mM * 5 mM) / 2 mM = 7.5 mM.

Consider the Following Interaction Between a Protein and Its Ligand ↔\harr↔

Consider the Following Interaction Between a Protein and Its Ligand $\harr$