A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 L to 2.00 L at constant temperature. After the compression, the gas pressure was atm.
A) 1.00
B) 16.0
C) 2.00
D) 8.00
E) 4.00

Question

Quizplus · Accepted Answer

Using the Boyle's Law equation (P1V1=P2V2) and plugging in the initial and final values, we can solve for the final pressure:

P2 = (P1V1)/V2
P2 = (4.00 atm * 8.00 L)/2.00 L
P2 = 16.0 atm

Therefore, the answer is B) 16.0.

A Sample of Gas (24