The reaction of 50 mL of N₂gas with 150 mL of H₂gas to form ammonia via the equation:
N₂(g) + 3H₂(g) - 2NH₃(g)
Will produce mL of ammonia if pressure and temperature are kept constant.

Question

Quizplus · Accepted Answer

According to the balanced equation: 1 mole of N₂reacts with 3 moles of H₂to form 2 moles of NH₃. We can use this ratio to determine how much ammonia will be produced from the given volumes of N₂and H₂: - Moles of N₂= (50mL/1000mL/L)(1 mol/L) = 0.05 mol - Moles of H₂= (150mL/1000mL/L)(1 mol/L) = 0.15 mol - Ratio of N₂to NH3 is 1:2, so moles of NH3 produced = 0.05 mol x (2 mol NH3/1 mol N₂) = 0.1 mol - Volume of NH3 produced = (0.1 mol)(22.4 L/mol) = 2.24 L = 2240 ml Therefore, the answer is D) 100 mL.

The Reaction of 50 ML of N2 gas with 150

The Reaction of 50 ML of N₂gas with 150