Using the following thermochemical data: 2Sm(s) + 6HF(g) → 2SmF3(s) + 3H2(g)
ΔrH° = -1929.4 kJ/mol-rxn
2Sm(s) + 6HCl(g) → 2SmCl3(s) + 3H2(g)
ΔrH° = -1498.0 kJ/mol-rxn
Calculate ΔrH° for the following reaction:
SmF3(s) + 3HCl(g) → SmCl3(s) + 3HF(g)
A) -3427.4 kJ/mol-rxn
B) 431.4 kJ/mol-rxn
C) 215.7 kJ/mol-rxn
D) 862.8 kJ/mol-rxn
E) -1713.7 kJ/mol-rxn
Correct Answer:
Verified
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