Determine ΔrH° for the following reaction,2 NH3(g) + 5/2 O2(g) → 2 NO(g) + 3 H2O(g) .The thermochemical equations for the reaction are given below: N2(g) + O2(g) → 2 NO(g)
ΔrH° = +180.8 kJ/mol-rxn
N2(g) + 3 H2(g) → 2 NH3(g)
ΔrH° = -91.8 kJ/mol-rxn
2 H2(g) + O2(g) → 2 H2O(g)
ΔrH° = -483.6 kJ/mol-rxn
A) -1178.2 kJ/mol-rxn
B) -452.8 kJ/mol-rxn
C) -394.6 kJ/mol-rxn
D) -211.0 kJ/mol-rxn
E) +1178.2 kJ/mol-rxn
Correct Answer:
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