A cylinder containing an ideal gas has a volume of 3.0 m³ and a pressure of 1.0 *10⁵ Pa at a temperature of 300 K. The cylinder is placed against a metal block that is maintained at 900 K, and the gas expands as the pressure remains constant until the temperature of the gas reaches 900 K. The change in internal energy of the gas is +6.0 *10⁵ J. How much heat did the gas absorb?

Question

Quizplus · Accepted Answer

The heat absorbed by the gas can be calculated using the first law of thermodynamics: ΔU = Q - W. Given ΔU = +6.0 x 10^5 J and the work done by the gas (W) is PΔV = 1.0 x 10^5 Pa x (9 m^3 - 3 m^3) = 6.0 x 10^5 J, we find Q = ΔU + W = 6.0 x 10^5 J + 6.0 x 10^5 J = 12 x 10^5 J.

A Cylinder Containing an Ideal Gas Has a Volume of 3.0